Calculating Average Acceleration in an Acceleration Test

AI Thread Summary
To calculate the average acceleration of a car in an acceleration test, the distance between two markers must be converted from kilometers to meters. The initial velocity is 5.0 m/s and the final velocity is 33.0 m/s, with the distance being 0.30 km (or 300 meters). The kinematic equation Vf² = Vi² + 2aav(d) can be rearranged to solve for average acceleration (aav). After correcting the distance unit, the calculations yield aav = 1773.3 m/s², which initially seemed incorrect due to the unit conversion oversight. Proper unit conversion is crucial for accurate results in physics problems.
CraZyFanAtiC
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Hey, guys just joined PF, was hoping you could help with this questions and in turn maybe i can return the favour (with the little physics knowledge I have).

Homework Statement


In a acceleration test, 2 markers are placed 0.30 km apart. The first car passed the first marked with a velocity of 5.0 m/s [E], the second passed the marker with a velocity of 33.0 m/s [E]. Calculate the Cars average acceleration.


Homework Equations


v1 = 5.0 m/s [E]
v2 = 33 m/s [E]
Delta D = 0.30 km
Aav = ?

The kinematics that i am using is Vf² = Vi² + 2aav(d)

The Attempt at a Solution


The problem i am having is rewriting the equation.
I need to rewrite this for aav.

Vf² - Vi² = Vi² + 2aav(d)

vf² - vi²/2(d) = aav

This is what i have so far, but it must be wrong i just don't see how. When i plug in the numbers..

1089 - 25/2(0.3) = aav
1064/0.6 = aav
aav = 1773.3

this can't be right can anyone help me?
 
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Hi CraZyFanAtic, welcome to PF.
Convert the distance from kilometer to meter.
 
rl.bhat said:
Hi CraZyFanAtic, welcome to PF.
Convert the distance from kilometer to meter.

O, wow do i feel stupid. First time I've seen a question like that just didn't think about it, thanks alot. Saved me a lot of time.
 

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