Calculating Average Distance Between Bright Fringes in a Double-Slit Experiment

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In a double-slit experiment, the average distance between bright fringes can be calculated using the formula nλ = d sin(θ), where n is the fringe number, λ is the wavelength, d is the slit separation, and θ is the angle to the fringe. For a setup with slits 0.10 mm apart and a screen 150 cm away, changing the screen distance to 3.0 m will affect the fringe spacing. Additionally, when using a wavelength of 5.00 × 10^-7 m, the distance between fringes is 0.40 cm, and altering the wavelength to 7.50 × 10^-7 m will also change this spacing. The discussion also touches on destructive interference in sound waves from two speakers, emphasizing the need for the correct formula to determine conditions for minimum intensity. Understanding these principles is crucial for accurately calculating fringe distances and interference patterns.
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1. A double-slit experiment is performed using a monochromatic light source, two slits spaced 0.10 mm apart, and a screen located 150 cm away. The bright fringes are located 0.30 cm apart. If the screen distance was changed to 3.0 m from the sources, what would the average distance between bright fringes become?

2. Again a double-slit experiment is performed using a monochromatic light source with a wavelength of 5.00 ´ 10–7 m. The pattern appears on a screen 150 cm away and the bright fringes are 0.40 cm apart. If the wavelength of the light used is changed to 7.50 ´ 10–7 m, what would the average distance between bright
 
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I don't think that i have the right formula to use for this question, but i know that for question 1
ë_1=5.00*10^-7m
L=1.5m
X= 0.004m
ë_2=7.5*10^-7m

Whats the formula? I think that if i have the formula for question 1 I can solve for 2.
 
Another question
Two speakers producing exactly the same frequency and always in phase are located on an east–west line. The sound is going north. The speakers are 50 cm apart and a microphone is located 80 cm due north of one speaker. Which of the following wavelengths would produce sound with the least intensity at the location of the microphone?

I drew a diagram and i understand how the speakers and mic are set up but i think that all i need is the formula for destructive interference. i have the formula sin(theta)=(n - 1/2)ë/d, but i don't think that its the right one b/c I don't have an angle of a nodal line #. What is the formula that I'm looking for?
 
Just so you know, there's an "Edit" button on your post. Instead of double posting and wasting space, simply press the edit button, and put your questions in your original post. Thanks.
 
For the first one you have to use an equation that looks like

n\lambda = dSin(\theta)

NOTE: those terms may not be correct, check your formula sheet

the n is the fringe number, lambda is wavelength, d is the distance between the lines in the diffraction grating (the inverse of the lines/m rating the grating has) and theta is the angle made between light going straight and going to one of the fringes.

To find theta, you have to use the inverse tangent of the distance between fringes divided by the distance between the diffraction grating and the screen.
 
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