Calculating Average Velocity of a Meteor using Radar Coordinates

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To calculate the average velocity of a meteor between two radar-determined points, the coordinates at point A are (5.60 km, 1.40 km) and at point B (6.12 km, 0.90 km). The user initially calculated the components of velocity as vx = 0.473 km/s and vy = -0.455 km/s but used an incorrect method to find the average velocity magnitude. The correct approach involves using the Pythagorean theorem to find the magnitude of the velocity vector, expressed as vav = sqrt((vx)^2 + (vy)^2). After clarification, the user acknowledged the mistake and confirmed understanding of the correct calculation method.
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Homework Statement



A meteor streaking through the night sky is located with radar. At point A its coordinates are (5.60 km, 1.40 km, and 1.10 s later its has moved to point B with coordinates (6.12 km, 0.900 km).

Find the magnitude of its average velocity between these two points

Homework Equations



none really

The Attempt at a Solution



I found the vx to be 0.473 km/s and vy to be -0.455 km/s. From this I took average velocity of the magnitude to be y/x to be -0.455/0.473. But the answer is wrong. Am I on the right track or am i doing it completely wrong? Please Help! Thanks
 
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"From this I took average velocity of the magnitude to be y/x to be -0.455/0.473"

Not sure what this...

Anyway, given the components vx and vy you have, the magnitude of this vector, and thus the average speed, is

vav = sqrt((vx)^2 + (vy)^2)
 
haha thanks, i figured it out that i was way off and should have used the pathagerom therom. thank you for the help anways!
 
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