Calculating Bearing Load for Linear Slides: Equation and Examples

AI Thread Summary
To calculate the bearing load for a linear slide with two spaced bearings and an extended load, apply the equations of static equilibrium. The sum of forces in the Y direction must equal zero, leading to the equation R1 + R2 - 30 = 0. Additionally, the sum of moments at one bearing point must also equal zero, resulting in R2 being calculated as 50kg. Substituting this value back into the force equation yields R1 as -20kg. This method effectively determines the bearing reactions needed for the slide.
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Homework Statement



Need to know the bearing load for a linear slide I'm working on, two spaced bearings with an extended load off the end of the slide.

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Homework Equations



What equation do I need to apply? What examples are out there?

The Attempt at a Solution

 
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You need to apply the equations of static equilibrium to determine R1 and R2.
 
I'm still not sure how to apply, I can't find any relevant examples. The two distances are 1.5m and 1m, bearing spread and mass extended.
 
R1 = 1/2.5*(30*1) = 12kg
R2 = 1/2.5*((30*2.5)+(30*1)) = 42kg

This is how I've done it, if anyone can give me some guidance that'd be great.
 
Use equilibrium equations

Lets assume both reactions (R1, R2) are facing upwards.

Now we do the sum of forces in the Y direction=0, where upwards is positive.

So, Sum of Fy=0: R1 + R2 - 30=0

Now let's take the sum of the moments at point 1 equal to zero, where anti-clockwise is positive.

So, Sum of M1=0: (1.5)(R2) -(2.5)(30)= 0
(1.5)(R2)=75
R2= 75/1.5
R2=50kg

Substituting in the 1st equation:

R1 + 50 -30 =0
R1 +20=0
R1= -20kg

So your reactions R1 and R2 are -20kg, 50kg respectively.
 
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Thanks I understand now, appreciate your help.
 
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