Calculating Block's Backward Pull in Physics Problem?

  • Context: High School 
  • Thread starter Thread starter mayodt
  • Start date Start date
  • Tags Tags
    Laws Newton's laws
Click For Summary
SUMMARY

The discussion centers on calculating the backward pull on a block being pulled by tension over a right-angle triangle inclined at 35.7 degrees. The key formula involves the component of gravitational force acting parallel to the incline, expressed as mass multiplied by gravity and the sine of the angle (mass x gravity x sin 35.7). The sine function is crucial as it determines the effective force acting along the incline, allowing for accurate calculations of the block's acceleration and backward pull.

PREREQUISITES
  • Understanding of basic physics concepts, specifically forces and motion.
  • Familiarity with trigonometric functions, particularly sine.
  • Knowledge of Newton's laws of motion.
  • Ability to analyze right-angle triangles in physics problems.
NEXT STEPS
  • Study the application of trigonometric functions in physics problems.
  • Learn about Newton's second law and its application in inclined plane scenarios.
  • Explore the concept of gravitational force components on inclines.
  • Review examples of tension forces in physics to solidify understanding.
USEFUL FOR

High school physics students, educators teaching mechanics, and anyone interested in understanding forces on inclined planes.

mayodt
Messages
14
Reaction score
0
Hey, I have a question I'm stuck on for my grade 12 physics class. There is a block being pulled by tension over a triangle essentially that's at a degree of 35.7 (right angle triangle). I understand the whole question but I don't understand how to find how much pull the block has backwards of it's acceleration? It says it's the mass x gravity x sin 35.7. Why is sin theta added in there? Sorry if this is difficult to understand, if I could draw the picture, this would be so much easier. Thanks if anyone understands my question/can help me out.
 
Physics news on Phys.org
They found the component of the gravitational force parallel to the incline. Read this: http://www.physicsclassroom.com/Class/vectors/u3l3e.cfm"
 
Last edited by a moderator:
Oh alright, I understand it now, thank you. I didn't think of it that way :biggrin:
 

Similar threads

  • · Replies 38 ·
2
Replies
38
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 27 ·
Replies
27
Views
2K
Replies
13
Views
3K
Replies
2
Views
2K