Calculating Car Acceleration: Kinematic Equations

AI Thread Summary
To calculate the car's acceleration after applying brakes, the kinematic equation Δd = VfΔt - 0.5aΔt² is correctly used. The distance of 14.6 meters and time of 2.1 seconds lead to the equation 14.6 = 0 - 0.5a(4.41). Simplifying this shows that the acceleration, which is negative due to deceleration, can be solved as a single unknown. The term "deceleration" is commonly used, but it is still classified as acceleration in physics. Understanding this distinction is important for accurately interpreting the results.
helpme2012
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Homework Statement



You are driving your car and you heavily apply the brakes for a period of 2.1 seconds. The car keeps moving for a distance of 14.6m before it completely stops.

What is the acceleration (in m/s2) experienced by the car? Is it truly "acceleration"?

Homework Equations



5 kinematic equations

The Attempt at a Solution


I was using this : Δd=VfΔt-0.5aΔt2

14.6=0(2.1)-0.5a(2.12)
14.6= 0-0.5a(4.41)

I don't know what to do after that, I don't know what to do with the part of the equation with the acceleration. Am I even using the right kinematic equation?
 
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You are using the right one! Note how you have a single equation with just one unknown, a - which is exactly what you're after.
So much for the physics part, you need to pull out your mathematical skills now and solve the equation. First, try simplifying 0.5 * 4.41 and 0 - ...
 
Notice the "0- " part. The acceleration will be negative. In everyday language we would call that "deceleration" but, technically, it is still a type of "acceleration".
 
helpme2012 said:

Homework Statement



You are driving your car and you heavily apply the brakes for a period of 2.1 seconds. The car keeps moving for a distance of 14.6m before it completely stops.

What is the acceleration (in m/s2) experienced by the car? Is it truly "acceleration"?


Homework Equations



5 kinematic equations

The Attempt at a Solution


I was using this : Δd=VfΔt-0.5aΔt2

14.6=0(2.1)-0.5a(2.12)
14.6= 0-0.5a(4.41)

I don't know what to do after that, I don't know what to do with the part of the equation with the acceleration. Am I even using the right kinematic equation?
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