How Do You Calculate Centripetal Force for Circular Motion?

  • Thread starter Thread starter joe465
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
To calculate the centripetal force for a 3 kg object rotating in a circle with a radius of 3 m at one revolution per second, the tangential velocity must first be determined, which is 18.85 m/s. The centripetal force is then calculated using the formula F = mv²/r, resulting in a force of approximately 355.31 N. A correction was noted regarding the use of revolutions per second instead of revolutions per minute, which clarified the calculation process. Additionally, alternative formulas for centripetal force that do not require calculating velocity were suggested for future reference. Understanding these concepts is essential for mastering circular motion dynamics.
joe465
Messages
93
Reaction score
0

Homework Statement



Calculate the centrepetal force required to rotate a3kg object in a circle at a radius of 3m at one revolution per second.

Homework Equations



MV2/r
2*pie*r

The Attempt at a Solution



First i presume i must convert the revolution per second into metres per second.

Calculate the circumference.

2*pie*r
2*pie*3
18.84955592153876m

Since its one revolution per second then it would mean:

18.84955592153876ms-1

Now for centrepetal force:

mv2/r

3*18.84955592153876 squared/3

1065.9172753176507952118585470128 / 3

Centrepetal force = 355.31N (2dp)


I hope this is right, the circular motion stuff still has never sunk in

Thanks, Joe
 
Physics news on Phys.org
Your calculation of the tangential velocity v is incorrect, you should use v= rω and then put that into F=mv2/r or F=mω2r for a more direct approach.
 
Looks good to me. :smile:
 
rock.freak667 said:
Your calculation of the tangential velocity v is incorrect,
Why do you say that?
 
Doc Al said:
Why do you say that?

Nevermind, my bad, I used rpm instead of what it was rps.
 
That's quite right. I would have written 355.3 N, but that's just my "three significant figures" training.

MIT Open Courseware has an excellent lecture series on Classical Mechanics, with a great video on circular motion.
 
joe465 said:

Homework Statement



Calculate the centrepetal force required to rotate a3kg object in a circle at a radius of 3m at one revolution per second.

Homework Equations



MV2/r
2*pie*r

The Attempt at a Solution



First i presume i must convert the revolution per second into metres per second.

Calculate the circumference.

2*pie*r
2*pie*3
18.84955592153876m

Since its one revolution per second then it would mean:

18.84955592153876ms-1

Now for centrepetal force:

mv2/r

3*18.84955592153876 squared/3

1065.9172753176507952118585470128 / 3

Centrepetal force = 355.31N (2dp)


I hope this is right, the circular motion stuff still has never sunk in

Thanks, Joe

There are many texts and references that show it, but if you look at the following wiki reference - the formulas right at the start - you will see that there is another formula for centripetal force that can be used in exactly this situation - when you know the Period of rotation rather than how fast it is travelling. That means you can't make a mistake calculating v, because you never calculate it!

http://en.wikipedia.org/wiki/Centripetal_force
 
Back
Top