Calculating Change in Momentum of a Softball After Bat Contact

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Homework Statement

Pitcher pitches a .30 kg softball has velocity 14 m/s at an angle of 36 degrees below the horizon just before the bat contacts the ball. What is the magnitude of change in momentum if the ball leaves the bat with a velocity of 23 m/s, vertically downward.

Homework Equations

v(i) = <14cos324, 14sin324> = <11, -4.3>
v(f) = <23cos270, 23sin270> = <0, -23>
Delta p = mv(f) - mv(i) = m [v(f) - v(i)]

The Attempt at a Solution

Delta p = .30(<0, -23> - <11, -4.3>) = <-3.3, -5.7>

Magnitude of delta p = sqrt[(-3.3)^2 + (-5.7)^2] = 6.6

 

[LowlyPion]

v(i) = <14cos324, 14sin324> = <11, -4.3>
v(f) = <23cos270, 23sin270> = <0, -23>

I'm not sure I follow your values for the components of the initial velocity.
I get ...

14 cosine36 = 11.34
14 sine 36 = 8.23

 

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You're right...not sure how my brain froze for that calculation...must have been a typo...thought I double-checked it! Thanks!