- #1
atmega-ist
- 9
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I've got the answer to the problem but I'm one decimal place off from the back of the book and am suspecting a typo (no, lol... not that presumptuous...) the reason for the suspicion is that there's a zero after the answer where the units would go but this question is asking for a coefficient of friction so, of course, there should be no units... I'm just wondering if that zero was somehow misplaced in printing/formatting... I could be completely missing something though.
A coin placed 30.0cm from the center of a rotating, horizontal turntable slips when its speed is 50.0cm/s. What is the coefficient of static friction between the coin and turntable?
[tex]\mu_{s}=\frac{v^{2}}{gr}[/tex]
[tex]\mu_{s}=\frac{.05m/s^{2}}{(9.81m/s^{2})*.03m/s^{2}}[/tex]
[tex]\mu_{s}=.0085[/tex]
The book states ".085 0"
Is my solution correct or am I missing something?
Thanks!
Homework Statement
A coin placed 30.0cm from the center of a rotating, horizontal turntable slips when its speed is 50.0cm/s. What is the coefficient of static friction between the coin and turntable?
Homework Equations
[tex]\mu_{s}=\frac{v^{2}}{gr}[/tex]
[tex]\mu_{s}=\frac{.05m/s^{2}}{(9.81m/s^{2})*.03m/s^{2}}[/tex]
[tex]\mu_{s}=.0085[/tex]
The Attempt at a Solution
The book states ".085 0"
Is my solution correct or am I missing something?
Thanks!