Calculating Commutator [H,U(m,n)] with Homework Statement

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Homework Help Overview

The problem involves calculating the commutator of a Hermitian operator \( H \), which represents a physical system's Hamiltonian, with the operator \( U(m,n) = |\phi(m)\rangle\langle\phi(n)| \), where \( |\phi(n)\rangle \) are the eigenstates of \( H \) forming an orthonormal basis. This is a quantum mechanics problem from a textbook.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the structure of the commutator and how to apply the operator \( H \) to the eigenstates. There are attempts to express \( H \) in terms of its eigenstates and eigenvalues. Some participants suggest using a superposition of eigenstates for the state \( |\psi\rangle \) to facilitate the calculation.

Discussion Status

Several participants have provided insights into the calculation process, noting the importance of correctly applying the operators and maintaining clarity in notation. There is an ongoing exploration of the implications of the commutator's result, with some participants proposing specific forms for the commutator based on the energy eigenvalues.

Contextual Notes

Participants are working under the assumption that the eigenstates \( |\phi(n)\rangle \) are orthonormal and that the operator \( H \) can be expressed in a particular form. There is mention of potential confusion regarding the notation and the application of operators to kets and bras.

Berny
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Homework Statement


|phi (n)> being eigen states of hermitian operator H ( H could be for example the hamiltonian
of anyone physical system ). The states |phi (n)> form an orthonormal discrete basis.
The operator U(m,n) is defined by:

U(m,n)= |phi(m)><phi(n)|
Calculate the commutator:
[H,U(m,n)]

( this is part of the first problem in Cohen, Tannoudji, Diu, Laloe textbook in quantum mechanics.)

The Attempt at a Solution

\

[HU-UH] (ψ) = H|phi(m)><phi (n)|ψ> - |phi (m)><phi(n)| H| ψ>

= <phi(n)|ψ> H |phi (m>) - |phi (m><phi(n)| <ψ | H

and then ? i did not find symbol phi.
 
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Note that the operator ##H## can be written as ##H=\sum\limits_{k}E_{k}\left|\phi(k)\right>\left<\phi(k)\right|##, where the ##E_{k}## are its eigenvalues. Also, note that the vectors ##\left|\phi(k)\right>## form an orthonormal set.
 
you should use an eigenstate of the Hamiltonian instead of \psi (if you ask how you can do that, you can expand \psi as a superposition of the Hamiltonian's eigenstates)
Then in general, following correct paths you will reach the desired result/
 
Berny said:

Homework Statement


|phi (n)> being eigen states of hermitian operator H ( H could be for example the hamiltonian
of anyone physical system ). The states |phi (n)> form an orthonormal discrete basis.
The operator U(m,n) is defined by:

U(m,n)= |phi(m)><phi(n)|
Calculate the commutator:
[H,U(m,n)]

( this is part of the first problem in Cohen, Tannoudji, Diu, Laloe textbook in quantum mechanics.)

The Attempt at a Solution

\

[HU-UH] (ψ) = H|phi(m)><phi (n)|ψ> - |phi (m)><phi(n)| H| ψ>

= <phi(n)|ψ> H |phi (m>) - |phi (m><phi(n)| <ψ | H

and then ? i did not find symbol phi.

many thanks for help. I find a commutator value depending upon the system energy :

commutator = E(m) U(m,n) if E= E(m) and - E(n) U(m,n) if E=E(n).

in other cases it's zero.
Is this correct ?
 
I got something like [H,U(m,n)] = (E(m)-E(n))U(m,n). The commutator does not depend on what state the quantum system is in.
 
Berny said:

Homework Statement


|phi (n)> being eigen states of hermitian operator H ( H could be for example the hamiltonian
of anyone physical system ). The states |phi (n)> form an orthonormal discrete basis.
The operator U(m,n) is defined by:

U(m,n)= |phi(m)><phi(n)|
Calculate the commutator:
[H,U(m,n)]

( this is part of the first problem in Cohen, Tannoudji, Diu, Laloe textbook in quantum mechanics.)

The Attempt at a Solution

\

[HU-UH] (ψ) = H|phi(m)><phi (n)|ψ> - |phi (m)><phi(n)| H| ψ>

= <phi(n)|ψ> H |phi (m>) - |phi (m><phi(n)| <ψ | H
You can say that ##\hat{H}\lvert \phi_m \rangle \langle \phi_n \vert \psi \rangle = \langle \phi_n \vert \psi \rangle \hat{H}\lvert \phi_m \rangle## because ##\langle \phi_n \vert \psi \rangle## is a number, though it doesn't really help you in this case. What you can't do is say ##\lvert \phi_m \rangle \langle \phi_n \lvert \hat{H} \rvert \psi \rangle## equals ##\lvert \phi_m \rangle \langle \phi_n \lvert \langle \psi \rvert \hat{H}## because ##\hat{H}\lvert \psi \rangle## and ##\langle \psi \rvert \hat{H}## aren't the same. One's a bra; the other, a ket. You need to be a bit more precise with your notation, otherwise you're invariably going to make errors.

You have, so far,
\begin{align*}
[\hat{H},\hat{U}] &= \hat{H}\hat{U} - \hat{U}\hat{H} \\
&= \hat{H}\lvert \phi_m\rangle\langle\phi_n\rvert - \lvert \phi_m\rangle\langle\phi_n\rvert\hat{H}
\end{align*} Now in the first term, apply ##\hat{H}## to the ket ##\lvert \phi_m \rangle##. What do you get? Similarly, in the second term, what do you get when ##\hat{H}## acts on the bra ##\langle \phi_n \rvert##?
 

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