Calculating conservation of Energy, Frictionless Oscillatory Motion

AI Thread Summary
The discussion focuses on using energy principles to verify the law of conservation of energy in a frictionless oscillatory motion scenario. The user provided specific mass, spring constant, equilibrium position, and various positions and velocities at different times. They attempted to apply the conservation of energy equation but arrived at incorrect results. It was pointed out that the user should utilize the correct simple harmonic motion equation to determine position and velocity accurately. Proper application of these equations is essential for confirming energy conservation in the system.
mgazaway72106
Messages
1
Reaction score
0

Homework Statement


Use energy to show whether or not the data agrees with the law of conservation and explain.

Mass-.3105kg spring constant-6.412 Equailibrium position-1.082
Max positive postion (1) farthest distance to the right of the equlibrium position
time-3.70s postion-1.303m Velocity-0.101m/s
Min positive position (2) farthest distance to the left of the equilibrium postion
time 4.40s postion .861m Velocity .061m/s
Max Velocity (3) near the equilibrium positon
time- 4.0s position-1.114m Velocity .981m/s

Homework Equations


http://en.wikipedia.org/wiki/Simple_harmonic_motion
I am in algebra based physics and haven't gone over a lot of the variables that are used in these equations. But I used the simple harmonic equations I added the kenetic to the potential in the spring. then set it equal to the potential in spring multiplied by time.
Ke+Pe=Pe(t3)

The Attempt at a Solution


.5mv2+.5kx2=.5kx2t3
my numbers ended up being
2.11=2.51
is this correct?
 
Last edited:
Physics news on Phys.org
No, this is not correct. The equation you used is incorrect - the equation for simple harmonic motion is x(t) = A cos(ωt + φ), where A is the amplitude of the motion, ω is the angular frequency, and φ is the phase shift. You need to use this equation to solve for the position and velocity of the object at each point.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top