- #1
LADransfield
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Hi, if I have a DC indoctor-resistor circuit with and inductance (L) of 700μH and a resistance (R) of 0.8Ω, I realize that I can use:
IL = (Vsource/R) * (1-e-t*(R/L))
to calculate the current through the inductor if I have a constant voltage source, but would it be possible to calculate how the current build (and also decay) might look in this or a similar method if my source voltage looked more like:
http://www.dransfield.talktalk.net/VoltageTrace.jpg
So far I can't work out how to make this work with a changing voltage, as the equation appears to assume that you always start at 0
Also, on the decay side, the equation:
IL = (Vsource/R) * (e-t*(R/L))
Seems to assume that you always start at current I=V/R, which is not always necessarily true
I hope I've explained myself well enough, and thanks for any help in advance!
IL = (Vsource/R) * (1-e-t*(R/L))
to calculate the current through the inductor if I have a constant voltage source, but would it be possible to calculate how the current build (and also decay) might look in this or a similar method if my source voltage looked more like:
http://www.dransfield.talktalk.net/VoltageTrace.jpg
So far I can't work out how to make this work with a changing voltage, as the equation appears to assume that you always start at 0
Also, on the decay side, the equation:
IL = (Vsource/R) * (e-t*(R/L))
Seems to assume that you always start at current I=V/R, which is not always necessarily true
I hope I've explained myself well enough, and thanks for any help in advance!
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