Calculating Displacement and Average Velocity/Acceleration for Circular Motion

AI Thread Summary
Average velocity and average acceleration are distinct vector quantities, with velocity being the rate of change of displacement and acceleration the rate of change of velocity. An object can have the same numerical value for average velocity and average acceleration, but their units differ, making them fundamentally different. In circular motion, even at a constant speed, the direction change results in acceleration. The discussion involves calculating the average velocity and acceleration of an athlete running on a circular track, emphasizing the importance of displacement and direction in these calculations. Correctly determining the displacement and average velocity requires understanding the positions of points on the track and their relationship to one another.
nwells1998
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What is the difference between average acceleration and average velocity?
 
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Velocity and acceleration are two different quantities. Velocity is the rate of change of displacement; acceleration is the rate of change of velocity.
 
So can an object have the same average velocity and average acceleration?
 
nwells1998 said:
So can an object have the same average velocity and average acceleration?
No, the units are different. You might have an object with an average velocity of 1 m/s and an average acceleration of 1 m/s², but those are not the same despite both having the number 1. Just like 1 orange is not the same as 1 apple.
 
An athlete starts at point A and runs at a constant speed of 6.0m/s around a round track 100m in diameter. find the x and y components of this runners average velocity and acceleration between points a, b, c, d (equally apart on circle).

So there is no acceleration because the speed is constant?
 
nwells1998 said:
An athlete starts at point A and runs at a constant speed of 6.0m/s around a round track 100m in diameter. find the x and y components of this runners average velocity and acceleration between points a, b, c, d (equally apart on circle).

So there is no acceleration because the speed is constant?
Both velocity and acceleration are vector quantities. In other words they have a magnitude and a direction. If you change the direction of your velocity you have accelerated even if you have not changed the magnitude of your velocity (speed).
 
ah...okay I see...thanks, i will start working on this problem!
 
So...tell can you please tell me if I am on the right track?

A = (-50, 0) B = (0,50) C = (50, 0) D = (0, -50)

Circumference = (pi * r^2) = 7854m

time between points = 7854m / 6.0m/s = 1309 s

X components:
Vax, A = (0-50m)/1309s = -0.038 m/s

Aax, A = (0-50m/s)/1309s = -.038m/s/s
 
nwells1998 said:
So...tell can you please tell me if I am on the right track?

A = (-50, 0) B = (0,50) C = (50, 0) D = (0, -50)

Circumference = (pi * r^2) = 7854m
Careful: You found the area instead of the circumference.

time between points = 7854m / 6.0m/s = 1309 s
Correct this. Also: The points are spaced 1/4 circumference apart.

To find the average velocity between points A and B, for example, first find the displacement between A and B. (It's a vector that points from A to B.)
 
  • #10
oops...okay so the circumference is 314m.

Time between points is 314m / 6.0m/s / 4 13.0s between each section.

so for A - b

displacement Ax = (0-50m)/13s = -3.84 m/s
displacement Ay, A = (50-0)/13s = 3.84 m/s

VA = sq rt[(-3.84^2)+(3.84^2)] = 5.43 m/s

Aax = 3.84m/s^2 Aay = -3.84m/s^2
 
  • #11
Hi nwells1998,

nwells1998 said:
oops...okay so the circumference is 314m.

Time between points is 314m / 6.0m/s / 4 13.0s between each section.

so for A - b

displacement Ax = (0-50m)/13s = -3.84 m/s
displacement Ay, A = (50-0)/13s = 3.84 m/s

I don't believe this is right for the displacement, even though some of your numbers are right. Let's say point A is 50m to the west of the circle and point B is 50 m to the north of the circle. To find the displacement, you need to know how far B is from A, and also what direction B is from A. What would those answers be?

Then the average velocity is found from:

average velocity = displacement / time

VA = sq rt[(-3.84^2)+(3.84^2)] = 5.43 m/s

Aax = 3.84m/s^2 Aay = -3.84m/s^2

The average acceleration is (change in velocity)/(change in time). To answer that, you need to know what the velocities are at A and B. What are those?
 
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