Calculating Distance Traveled for Two Skaters

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To calculate the distance traveled by the 9.2 kg skater, the center of mass of the system must be determined. The center of mass is found using the formula that considers the masses and their positions. Given the masses of 9.2 kg and 3.0 kg, the center of mass is located closer to the heavier skater. The 9.2 kg skater travels approximately 2.13 m before stopping, assuming negligible friction. The calculations confirm this distance is correct.
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Two skaters of mass 9.2 kg and mass 3.0 kg stand 8.7 m apart, each holding the end of a rope stretched between them. If each skater pulls himself along the rope until they both meet how far (in m) has the person with the mass of 9.2 kg travel before stopping. Assume that friction is negligible. (Hint: make the 9.2 kg skater your zero reference point and find the center of mass)

X=2.13m?

I don't have time to type my work right now. But will show work if answer is wrong to see where i went wrong.
 
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