Calculating Efficiency and Work in Otto Cycle Engine

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The efficiency of an Otto cycle engine with a compression ratio of 6 and a heat input of 350 kJ is calculated using the formula Efficiency Otto = 1 - r^(1-k), where k is the ratio of specific heats (Cp/Cv). The correct calculation yields an efficiency of approximately 55.34%. The work done by the engine is determined by multiplying the efficiency by the heat transferred, resulting in approximately 193.72 kJ. There was a correction noted regarding the use of exponents in the formula. Accurate calculations are essential for determining engine performance.
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Homework Statement



An Engine works within Otto cycle where the compression ratio is 6, and 350 kJ of heat was added to it. Determine the efficiency of the cycle and the work done if Cp/Cv is 1.45

Homework Equations


Efficiency Otto = (1- r1-k)
Efficiency (eff.) =Work (W) /Heat Transferred (Q)

The Attempt at a Solution



Efficiency Otto = (1- r1-k) ( r is the compression ratio, k is Cp/Cv)

= 1-61-1.45

= 0.5534 = 55.34% --> The efficiency of the cycleW=eff. * Q = 0.5534 * 350

W=193.72 kJ --> The work done
 
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Your result looks fine, but use the "x2" button for an exponent. The efficiency is 1-r(1-k) instead of 1-r1-k and 1-61-1.45 is not 55.34%.
 
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