Calculating Efficiency of an Ottos Cycle: I Need Help!

  • Thread starter Thread starter Kork
  • Start date Start date
  • Tags Tags
    Cycle Efficiency
AI Thread Summary
The efficiency of an Otto cycle is calculated using the formula η = Wnet/W12. The user has determined an efficiency of 0.20, indicating that the system is 20% efficient. This means that only 20% of the input energy is converted into work, while 80% is lost as heat. Understanding this efficiency is crucial for evaluating the performance of the engine. The discussion highlights the importance of efficiency in energy conversion processes.
Kork
Messages
33
Reaction score
0
I have made an Ottos Cycle graph and found the area Wnet and W12. I now have to find the efficiency η = Wnet/W12 I have found that to be 0,20 but I have no idea what this tells me about the work or anything.

I need help.
 
Physics news on Phys.org
If \eta=.2 then the system is 20% efficient, that is, if you put some energy into the system, only 20% of that energy is converted into work, and the other 80 percent is lost as heat.
 

Similar threads

Engineering Reviewing Efficiency of Otto & Diesel Cycle Heat Engines
Replies
8
Views
3K
Engineering Understanding Rankine Cycle Pressures: Should P2 Equal P3?
Replies
1
Views
1K
Solve Otto Cycle Problem: Heat Rejection (300 kW)
Replies
4
Views
6K
Rankine Cycle Thermal Output Calculation for 1000 MWe
Replies
1
Views
2K
Thermal efficiency of the Rankine cycle
Replies
9
Views
3K
I Are Qin and W equivalent in the Rankine and Otto cycles?
Replies
3
Views
2K
Efficiency of Stirling Cycle - Is it the same as the Carnot Engine?
Replies
14
Views
1K
Steam Power Plant Reheat Efficiency Calculation
Replies
4
Views
2K
Rankine Cycle Efficiency Calculation - Superheated Steam at 40 bar and 500°C
Replies
8
Views
3K
Otto Cycle - calculate the net work per cycle in Btu
Replies
7
Views
6K

Hot Threads

Recent Insights

Back
Top