Calculating Electric Fields Using Gauss' Law and Symmetry

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An infinite sheet of charge with a uniform charge density of 6.0 x 10^-5 C/m^2 is located on the y-z plane, while a point charge of 3.4 x 10^-7 C is positioned at (0.03m, 0, 0). To calculate the electric fields at specified points, the electric field from the sheet can be determined using Gauss' Law, taking advantage of the symmetry, which indicates that the field is normal to the surface. The electric field produced by the point charge can be calculated using Coulomb's Law. The total electric field at each location is the vector sum of the fields from both the sheet and the point charge.
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A diagram shows an infinite sheet of charge, uniform charge density = 6.0 x 10^-5 C/m^2 lying on the y-z plane. The sheet is of zero thickness. Q is a point charge of 3.4 x 10^-7 fixed at the point x(Q)= .03m, y(Q)=z(Q)=0.

calculate the the electric fields at the four locations...

(0.001m,0,0)
(-0.001m,0,0)
(0.001m, 0.03m,0)
(-0.001m, 0.03m, 0)
These electric fields must be given in terms of i, j and k hat
 
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You can separately calculate the electric field produced by the sheet charge and the point charge. Just add the results.
 
how do you calculate the electric field produced by the sheet of charge? Is that coulombs law? please, i need more help with this question.
 
To calculate the electric field due to the sheet charge use Gauss' Law and exploit the symmetry of the problems. Clearly, the electric field will be symmetric about the plane (the field will be normal to the surface) so construct a gaussian surface say in the form of a cylinder whose axis is normal to the plane with the ends equidistant from the plane.
 
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