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## Homework Statement

A 2cm x 3cm rectangle lies in the xy plane. What is the electric flux through the rectangle if

Electric field= (100i +50k) N/C

## Homework Equations

Φ

_{e}=E⋅Acosθ (Electric Flux Equation)

## The Attempt at a Solution

My question is to find the magnitude of the electric field we say E

_{mag}=√(100i)

^{2}+(50k)

^{2}= 111.8N/C

Area=6x10

^{-4}m

^{2}

To find direction θ=tan

^{-}(50/100)=26.5°

We know that The angle in formula for electric flux is the angle subtended from a line normal to the surface and the electric field line. Therefore 90°-26.5°=63.4°

so:

Φ

_{e}=E⋅Acosθ=(111.8N/C)(6x10

^{-4}m

^{2})cos(63.4)=3.0x10

^{-2}

The textbook is disagreeing with this answer... Not sure what I am doing wrong.