A 2cm x 3cm rectangle lies in the xy plane. What is the electric flux through the rectangle if
Electric field= (100i +50k) N/C
Φe=E⋅Acosθ (Electric Flux Equation)
The Attempt at a Solution
My question is to find the magnitude of the electric field we say Emag=√(100i)2+(50k)2= 111.8N/C
To find direction θ=tan-(50/100)=26.5°
We know that The angle in formula for electric flux is the angle subtended from a line normal to the surface and the electric field line. Therefore 90°-26.5°=63.4°
The textbook is disagreeing with this answer... Not sure what I am doing wrong.