Calculating Electron Deflection in a Ballistic Electron Transistor

AI Thread Summary
In the context of ballistic electron transistors, the problem involves calculating the time required for a vertical force to achieve a specific deflection angle of 131° for an electron colliding with a 45° wall. The known parameters include the electron's mass, the vertical force applied, and its initial velocity components. To solve for the time, the acceleration in the y-direction must first be determined, followed by calculating the necessary vertical velocity. The relationship between the angles and velocities is established through trigonometric functions, specifically using the tangent to find the required velocity components. Ultimately, these calculations lead to the time duration for the vertical force application needed to achieve the desired deflection angle.
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Homework Statement



In nanoscale electronics, electrons can be treated like billiard balls. The figure shows a simple device currently under study in which an electron elastically collides with a rigid wall (a ballistic electron transistor). The green bars represent electrodes that can apply a vertical force of 7.60·10-13 N to the electrons. If an electron initially has velocity components vx = 1.30·105 m/s and vy = 0 and the wall is at 45°, the deflection angle θD is 90°. How long does the vertical force from the electrodes need to be applied to obtain a deflection angle of 131°?

Homework Equations



Force*Delta.Time = Mass*Delta.Velocity

The Attempt at a Solution



I've spend a long time trying to figure this out. I'm trying to set Force*Delta.Time = Mass*Delta.Velocity.

I know that the mass is 9.11 10^-31, the force is 7.60·10-13, and I need to find the velocity to solve for the time.

I'm not sure how to find the velocity.

Thanks for any help.
 
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The vertical force on the electron is given. Mass of the electron is known. Find acceleration in the y direction.
Vx is given. Find Vy by Vy = a*t.

The velocity with which the electron hits tilting wall is given by

V = sqrt(Vx^2 + Vy^2) making an angle θ such that tanθ = (Vy/Vx) with horizon.

Angle made by the velocity to the inclined wall is (45 - θ).

To make the deviation 131 degrees, the velocity must make an angle 65.5 degrees with the normal to the inclined wall.
So 65.5 = 90 - ( 45 - θ)

Solve for θ and find tanθ.

From that you can find Vy and hence t.
 
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