Calculating Electron Mass from Magnetic Field and Potential Difference

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    Physics Physics 12
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The discussion revolves around a Grade 12 physics problem involving the calculation of electron mass using a magnetic field and potential difference. The magnetic field is given as 3.4E-3 T, and the potential difference is 250 V, leading to a derived electron mass of 7.25E-31 kg, which is lower than the known mass of 9.11E-31 kg. Participants confirm the calculations using the formula m = (B^2 q (2r)^2) / (8V) and arrive at the same result. There is a suggestion to verify the problem's details, particularly the magnetic field value. The conversation concludes with confidence in the calculations based on consistent results among users.
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I don't know if this is the place to post this, but This is a simple Grade 12 Physics question that I have been working on for about half an hour now.

For those who don't normally use this notation,
2E10 = 2X10^10.
2E-2 = 2X10^-2

"A magnetic field of 3.4E-3T deflects electrons into a circular path of radius .014m. The electorns have been accelerated through a potential differenc eof 250V. If the charge of an electron is 1.6E-19C, what is the mass of the electron?"

I have done it three times, and I keep getting 7.25E-31Kg when in actuality, a real electron is 9.11E-31Kg
 
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Do you really mean 3,400 tesla? I doubt it.

- Warren
 
sorry.. i'd make that 3.4E-3T
(.0034)
 
I did this question from a worksheet, and we both got identical answers.

If you have the same answer that my friend and I do, then chances are it is correct.

Thanks for your help!
 
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