Calculating EMF in Steel Beam Impact Before Landing

AI Thread Summary
The discussion revolves around calculating the electromotive force (emf) generated in a steel beam dropped from a height of 9.51 meters, with a length of 11.2 meters and a horizontal magnetic field of 18.5x10^-6T. The area of the beam is calculated as 53.36 m² using the formula for the area of a triangle, but its relevance to the emf calculation is questioned. The equation e = magnetic flux/time is referenced, yet the absence of a time variable complicates the solution. Participants express uncertainty about how to incorporate time into the calculation, and there is a consideration of the forces acting on a test charge within the beam. The discussion highlights the challenge of applying theoretical equations to practical scenarios in electromagnetism.
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Homework Statement



A 11.2m long steel been is dropped from a height of 9.51m. The horizontal component of the Earth's over the region is 18.5x10^-6T. What's the emf in the beam impact just before the impact with the earth, assuming its long dimension remains in a horizontal plane, oriented perpendicularly to the horizontal component of the Earth's magnetic field?

Homework Equations


e= mag flx/t


The Attempt at a Solution


A= 1/2*b*h
A=1/2 x 11.2 x9.51= 53.36

18.5e-6* 53.26
but there's no time
 
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xswtxoj said:

Homework Statement



A 11.2m long steel been is dropped from a height of 9.51m. The horizontal component of the Earth's over the region is 18.5x10^-6T. What's the emf in the beam impact just before the impact with the earth, assuming its long dimension remains in a horizontal plane, oriented perpendicularly to the horizontal component of the Earth's magnetic field?

Homework Equations


e= mag flx/t


The Attempt at a Solution


A= 1/2*b*h
A=1/2 x 11.2 x9.51= 53.36
That would be the area of a triangle, but I fail to see the relevance?

18.5e-6* 53.26
but there's no time

My own hunch is that the electric and magnetic forces on a test charge Q in the beam would have to be equal in magnitude, opposite in direction.

So, what is the magnetic force on a charge Q?
 
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