Calculating Emission Wavelength for Excited Atoms at 3.031x10^-19 J Energy Level

AI Thread Summary
To calculate the emission wavelength for excited atoms at an energy level of 3.031×10^-19 J, the relevant equation is λ = hc/E. Here, h represents Planck's constant (approximately 6.626 x 10^-34 J·s) and c is the speed of light (approximately 3.00 x 10^8 m/s). Substituting these values into the equation allows for the determination of the wavelength. The discussion emphasizes the importance of understanding these constants to solve the problem effectively. Accurate calculations will yield the desired emission wavelength for the excited atoms.
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Homework Statement
A sample of excited atoms lies 3.031×10^−19 J above the ground state. What is the emission wavelength of these atoms?
Relevant Equations
E=hc/λ
Problem Statement: A sample of excited atoms lies 3.031×10^−19 J above the ground state. What is the emission wavelength of these atoms?
Relevant Equations: E=hc/λ

λ=hc/E

I'm stuck on the first part. i.e;

something / 3.031x10^-19J
 
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pishogues said:
Problem Statement: A sample of excited atoms lies 3.031×10^−19 J above the ground state. What is the emission wavelength of these atoms?
Relevant Equations: E=hc/λ

something / 3.031x10^-19J

What is ##h##? what is ##c##?

If you don not know, go to "photon energy" wiki page.
 
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