Calculating Equilibrium Concentrations for a Gas Equilibrium Problem

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The discussion focuses on the equilibrium concentrations of PCl5, PCl3, and Cl2 in a reaction where PCl5 is 45% decomposed in a 1.00 L container. Starting with 0.110 mol of PCl5, the calculation shows that 45% of this decomposes, resulting in 0.0495 mol of PCl5 remaining. The remaining concentration of PCl5 is calculated to be 0.0605 mol/L. Since the reaction produces PCl3 and Cl2 in a 1:1 ratio, the amounts of PCl3 and Cl2 formed are also 0.0495 mol each. The final equilibrium concentrations are 0.0605 mol/L for PCl5, and 0.0495 mol/L for both PCl3 and Cl2.
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PCl5 <---> PCl3 + Cl2
all are gases

PCl5 is 45% decomposed
if .110 mol of PCl5 is put in a 1.00 L container, what will
be the equilibrium concentrations of PCl5, PCl3, and Cl2?

PCl5 = .110 * .45 = .0495
.110-.0495= .0605 mol/L

so I've got .0605 mol/L for all 3 since all have the
same coeff. Is this how to solve?
 
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0.110 - 0.0495 = 0.0605

So there's 0.0605 mol of PCl5, but how much PCl5 reacted? Therefore how much product was formed?
 
.0495 mol of PCl3
.0495 mol of Cl2

right?
 
You got it.
 
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