- #1
oxide
- 2
- 0
PCl5 <---> PCl3 + Cl2
all are gases
PCl5 is 45% decomposed
if .110 mol of PCl5 is put in a 1.00 L container, what will
be the equilibrium concentrations of PCl5, PCl3, and Cl2?
PCl5 = .110 * .45 = .0495
.110-.0495= .0605 mol/L
so I've got .0605 mol/L for all 3 since all have the
same coeff. Is this how to solve?
all are gases
PCl5 is 45% decomposed
if .110 mol of PCl5 is put in a 1.00 L container, what will
be the equilibrium concentrations of PCl5, PCl3, and Cl2?
PCl5 = .110 * .45 = .0495
.110-.0495= .0605 mol/L
so I've got .0605 mol/L for all 3 since all have the
same coeff. Is this how to solve?