Calculating Equilibrium Mass in a Pulley System

AI Thread Summary
To find the mass necessary for equilibrium in a pulley system, the sum of the net torques must equal zero. The initial calculation incorrectly used a factor of 3 for the number of cables supporting the truck's weight, leading to an incorrect mass of 353 kg. Upon realizing that two cables are actually supporting the truck, the correct mass is determined by dividing the initial result by two, yielding approximately 178 kg. The discussion emphasizes the importance of recognizing mechanical advantage in pulley systems. Understanding the number of supporting cables is crucial for accurate calculations in such problems.
twerkit
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Homework Statement



Find the mass necessary for equilibrium to occur in the following image. Assume that the mass and the friction of the pulleys are negligible.

giiiiirl-1.png


Homework Equations



None directly provided for this problem.

The Attempt at a Solution



I figured for this problem I would set the sum of the net torques on the pulley equal to zero, because then the pulley is not spinning and the system is in equilibrium.

Here is my equation:

gravity = 9.8 m/s

Since torque is the cross product of the force times the perpendicular distance from the axis of rotation, I used counterclockwise torque (provided by the truck) = F*rsin(x), but since the force is already perpendicular to the axis of rotation in the image I just used F*r, where the F = 1500*9.8*sin(45). The clockwise torque on the pulley is m*g*3r

ƩT = 1500kg*9.8*sin(45)*r - m*g*3r = 0

add m*g*3r to both sides and then divide by r to obtain:

ƩT = 1500kg*9.8*sin(45) = m*g*3

solving for the mass I get 353 kg, but the answer is 178 kg.

I noticed that multipying the right side by 6 instead of 3 yields the right answer, I just don't know why or what I'm doing wrong.
 
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How many cables support the truck's weight?
 
gneill said:
How many cables support the truck's weight?

I don't know, the question is literally this :

"Find the mass necessary for the truck to be balanced on the slope in the figure. Assume that the mass and frictions of the pulleys are negligible."

That is all it says, no information regarding how many cables or the like is given.
 
twerkit said:
I don't know, the question is literally this :

"Find the mass necessary for the truck to be balanced on the slope in the figure. Assume that the mass and frictions of the pulleys are negligible."

That is all it says, no information regarding how many cables or the like is given.

Doesn't the picture make it clear? How many cables with tension T are holding the truck?

(Think: mechanical advantage)
 
gneill said:
Doesn't the picture make it clear? How many cables with tension T are holding the truck?

(Think: mechanical advantage)

Ah, I thought you were asking me as if you needed more information! So since two cables are supporting the truck, I divide my answer by two and get approximately 178 kg.
 
That looks about right. Well done.
 
gneill said:
That looks about right. Well done.

Thank you for the eye opener :-)
 
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