Calculating errors (propagation)

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To calculate the error in Z, the formula Z = 2AB^2/C is used with given values for A, B, and C along with their respective errors. The calculated value of Z is 0.04. To propagate the errors, the partial derivatives of Z with respect to A, B, and C are determined, and the errors are combined using the formula for error propagation. The final result should express Z as 0.04 ± X.XX, where X.XX represents the calculated uncertainty. Understanding error propagation is essential for determining the range of possible values for Z.
pwphysics101
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Completely new to the concept of errors and don't know how to approach this...

Calculate value and error in Z

Z= 2AB^2/C


Where
A= 100 Error in A= +/- 0.1
B= 0.1 Error in B= +/- 0.005
C= 50 Error in C= +/- 2


Plugging in the numbers Z= 0.04

How do you carry the errors over into the equation? I think the answer is suppose to look like (0.04 +/-X.XX)..

Thanks for any help..
 
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As I understand it, the error is simply the widest possible range the value of Z could have. This is all I will say.
 

Thread 'Finding the number of ways to arrange identical balls in a circle (3 different colors)'

I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
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