Calculating Force and Normal Force on 10kg Suitcase at Angle 48

[BallerRegis]

A) You drag a suitcase of mass 10 kg with a
force of F at an angle 48 with respect to
the horizontal along a surface with kinetic
coefficient of friction 0.32.
The acceleration of gravity is 9.8 m/s2 .
If the suitcase is moving with constant
velocity 2.25 m/s, what is F?
Answer in units of N

B) What is the normal force on the suitcase?
Answer in units of N

C) If you pull the suitcase 66.1 m, what work
have you done?
Answer in units of J

D) If you are accelerating the suitcase with acceleration
1.43 m/s2 what is F?
Answer in units of N

I tried 46.511 for part A n got it wrong.

 

[theCandyman]

You're going to have to show more work, not just say you tossed in a value and got the incorrect answer.

That said, since you haven't shown any work, I'll give you an idea of how to attack the first part of the problem.

a) The suitcase is moving at a constant speed, so the force of friction is equal (but opposite in direction) to the force on the suitcase in the direction of motion (the x-component of F). Keep in mind that F has a y component when you calculate the frictional force.

 

[BallerRegis]

I did .32*(mg-sin48) divided by cos 48 and got 46.511