Calculating Force for an Exceptional Standing Jump | 70kg Person | 0.80m Height

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To calculate the force a 70kg person must exert for an exceptional standing jump of 0.80m, one can use either kinematic equations or conservation of energy principles. The kinematic approach involves determining the required velocity to reach 0.80m and the necessary acceleration to achieve that velocity over a 0.20m lowering distance. Alternatively, the energy method focuses on the conservation of mechanical energy, equating initial and final kinetic and potential energies. Both methods provide a framework for solving the problem, emphasizing the relationship between force, acceleration, and energy. Understanding these concepts is crucial for accurately calculating the required force for the jump.
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An exceptional standing jump would raise a person 0.80 m off the ground. To do this, what force must a 70kg person exert against the ground? Assume the person lowers himself .20m prior to jumping?

Ok, i know i need to find the acceleration and use the Fnet=ma equation but where do i start first?
 
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There are two ways to look at this problem. One way is conservation of energy, the other is kinematic.

For kinematic, you might first look at what velocity is necessary to "throw" an object straight up 0.80 m. Once you have this, then you can look at what acceleration is necessary to reach this velocity within 0.20 m.
 
The energy method is also interesting. Consider the final and initial mechanical energy (which is conserved because this is an isolated system). Remember that E_{Mechanical}=E_{Kinetic}+E_{Potential} here.
 
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