Calculating Force on a Child Riding a Ferris Wheel

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To calculate the force on a child riding a Ferris wheel at the highest point, the gravitational force acting on the child is 490 N. The angular velocity of the Ferris wheel is 0.2(pi) rad/s, leading to a radial acceleration of approximately 197.39 N. The normal force exerted by the seat is essential to determine, as it counteracts the gravitational force and provides the necessary centripetal force. The relationship between these forces is expressed as F_net = F_centripetal, with the normal force being equal to the centripetal force minus the gravitational force. This approach successfully calculates the net force acting on the child.
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A 50 kg child riding a farris wheel (radius= 10m) travels in a vertical circle. The wheel completes one revolution every 10 seconds. What is the magnitude of the force on the child by the seat at the highest point on the circlular path?

I found the Force due to gravity is mg = 490 N
angular velcity w= 0.2(pi) rad/s
and the force due to radial acceleration ar=(w^2)*R*m= 197.39 N

Is that all the forces I need to find, what exactly do I do. Thanks for the help.
 
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The force on the child by the seat would be the normal force. Essentially, you need to find how the magnitude of this force.
 
Yea i know, but the normal force would just be the oppisite of the sum of the forces "going down." Am I missing a force I need calculate or have I made a mistake?
 
I believe that since
F_{net}=F_{centripetal},
F_{normal}=F_{centripetal}-F_{g}
 
thank you that worked
 
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