Calculating Force Problems on Toy Car

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To calculate the inward force required for a toy car moving in a circular track, the formula F=mv²/r is used, yielding a result of 5.32 N for a car with a mass of 7.79 kg and a final speed of 5.13 m/s. The tangential force, needed to accelerate the car from rest to its final speed over 6 seconds, can be determined using linear force principles. The acceleration is calculated as the change in velocity divided by time, leading to a tangential force calculation. The user successfully found the solution to the tangential force problem after some guidance. This discussion highlights the application of physics formulas in solving force-related problems for circular motion.
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[SOLVED] force problems

A 7.79 kg toy car now starts at rest and is going around a circular track of radius 38.5 m, the accelerates at a constant rate to a final speed of 5.13 m/s in 6 seconds. At the instant it reaches its final speed, find:1.the magnitude of the inward force needed to keep it moving in a circle
2.the magnitude of the tangential force

F=ma
a=v2/r

question1. F=mv2/r=7.79(5.13)(5.13)/38.5=5.32. and that's is right.
question2. the magnitude of the tangential force, i don't know what to do with it ,can anybody help me?
 
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The tangential force problem is the same as a linear force problem. 0->5.13m/sec in 6sec. How much force?
 
thank you for help. i got the answer.
 

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