Calculating Force Required to Pull Copper Ball Upward

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To calculate the force required to pull a copper ball of radius 3.00 cm upward through a fluid at a constant speed of 9.00 cm/s, the mass of the copper ball must first be determined. The drag force, which opposes the upward motion, is proportional to the speed with a constant of 0.950 kg/s. Since the ball moves at a constant velocity, the net force acting on it is zero, indicating that the upward force equals the drag force. This scenario aligns with Newton's First Law of Motion, confirming that the ball is in a state of equilibrium. The discussion emphasizes the importance of understanding forces in fluid dynamics and their relationship to motion.
shiri
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Calculate the force required to pull a copper ball of radius 3.00 cm upward through a fluid at the constant speed 9.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force.

For this question, do I have to find the mass of a copper ball first, right?
 
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shiri said:
Calculate the force required to pull a copper ball of radius 3.00 cm upward through a fluid at the constant speed 9.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force.

For this question, do I have to find the mass of a copper ball first, right?
You've got an unknown force pulling up, and a drag force acting down. Anything else acting down?
 
Hello shiri, remember when the speed is constant we have the special case of 1st Law of Newton.
 
Cyclovenom said:
Hello shiri, remember when the speed is constant we have the special case of 1st Law of Newton.

if the net force is zero, so is that mean the copper ball is in a constant velocity?
 
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