Calculating Force to Accelerate Lawn Mower: Newton's 2nd Law

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To calculate the force needed to accelerate the lawn mower, the horizontal friction force is identified as 55.11 N, and the normal force is 190.8 N. The lawn mower, with a mass of 13 kg, must reach a speed of 1.3 m/s in 2.0 seconds, requiring a net force determined by Newton's second law. The equation F = 84 cos(49) + F(friction) = ma is suggested for setup, considering the angle of the handle. It is important to account for how the person's force affects the normal and friction forces while ensuring the calculations reflect the mower's horizontal position.
kgood5885
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I figured out the horizontal friction force, Fpx to be 55.11 N and the normal force exerted vertically to be 190.8 N. And the other info given is F = 84 the lawn mower has a mass of 13 kg and moves at a constant speed. The lawn mower is at an angle of 49 degrees to the horizontal. I need to determine the force the person must exert on the lawn mower to accelerate it from rest to 1.3 m/s in 2.0 seconds (assuming the same retarding force).
Do I use the equation 84 cos 49 + F (friciton) = ma? Or how do I set up this problem?
 
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If the person's Force is along a 49 degree handle
(while the lawn mower itself is on level?)
the person's force will increase the N required,
and might increase the friction Force.

Does your friction stay at 84 cos(49) ?
then get Fx_extra = ma_x
 
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