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Calculating Forces on Charged Particles Using Vector Components
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Use the formula for electric field causing a force on a charge: Fe = q*E
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got that. that's where the 1.6 x 10^-4 came from.
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Are you finished then, or do you need to add the electric field due to the other charge? A good idea to show formula and numbers - the answer is not much of a clue as to what you have done.
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electric field strength is on the image - 20 N/C
the issue here is, they want it in i, j k format
the issue here is, they want it in i, j k format
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Okay.
1.6 x 10^-4 * cos(60) i + 1.6 x 10^-4 * sin(60) j + 0k
1.6 x 10^-4 * cos(60) i + 1.6 x 10^-4 * sin(60) j + 0k
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thanks delphi. can you explain the cos and sin portion a bit? i never really could understand why those are used to express a single side of a triangle
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Expressing a vector as a horizontal part plus a vertical part makes it very convenient to add vectors (just add the h and v parts separately without worrying about angles). Also, in something like a trajectory problem the motion in two perpendicular directions is independent, so you can do the horizontal part of the problem without worrying about the vertical part.