Calculating Frictional Force of a Sliding Mass

AI Thread Summary
To calculate the frictional force of a sliding 10.0-kg mass on a 25.0-degree incline, the coefficient of sliding friction (0.520) is used with the formula F_friction = μmgcosθ, resulting in a frictional force of 46.19 N. Additionally, the downward force along the ramp is determined by mg*sin(25). The net force along the ramp is the difference between this downward force and the frictional force. A free-body diagram is recommended to visualize the forces acting on the mass, including the normal force. Understanding these components is crucial for solving the problem effectively.
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Homework Statement



A 10.0-kg mass is placed on a 25.0o degree incline and friction keeps it from sliding. The
coefficient of static friction in this case is 0.580, and the coefficient of sliding friction is
0.520. The mass is given a shove causing it to slide down the incline.

Homework Equations



What is the frictional
force while the mass is sliding?

The Attempt at a Solution



This is all I have so far, but I don't exactly understand it:

Frictional force while the mass is sliding = μmgcosθ = 0.52 X 10 X 9.8 X cos 25
= 46.19 N


I need a full step-by-step explanation, if possible. I'll also take any other information about the problem that may make it easier. Thank you.
 
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Your 46.19 is correct.
You also need to find the downward, along the ramp force. It is the other component of mg, that is mg*sin(25). The net force along the ramp is this force minus the friction force.

I always draw the ramp, put the mass at the very top and draw the mg force vector straight down. Then separate that mg into the sum of a force along the ramp and perpendicular to the ramp. The perpendicular force is the normal force pulling the mass against the ramp surface.
 


Welcome to PF;
Draw a free-body diagram for the mass and you'll see how that relation was found.
 


Delphi51 said:
Your 46.19 is correct.
You also need to find the downward, along the ramp force. It is the other component of mg, that is mg*sin(25). The net force along the ramp is this force minus the friction force.

I always draw the ramp, put the mass at the very top and draw the mg force vector straight down. Then separate that mg into the sum of a force along the ramp and perpendicular to the ramp. The perpendicular force is the normal force pulling the mass against the ramp surface.

Simon Bridge said:
Welcome to PF;
Draw a free-body diagram for the mass and you'll see how that relation was found.

I'll do all of the above. Thank you.
 


Cool! Let us know how you get on.
 
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