- #1
wakadarc
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I need to determine the RPM just that the flywheel (that has an offset shaft) will travel faster than gravity (g force). Meaning my offset shaft will be falling faster than a falling object per se.
So flywheel has a diameter of 0.1524m.
h=1/2g*t^2
t=0.144s (assuming we did 1.5x(9.8m/s) with h=0.1524m)
angular velocity = 3.14/t = 3.14/0.144s = 21.82 rad/s
Therefore the RPM is 208 RPM (1 rad/s = 9.55 RPM)
Is this the right approach? Thank you.
So flywheel has a diameter of 0.1524m.
h=1/2g*t^2
t=0.144s (assuming we did 1.5x(9.8m/s) with h=0.1524m)
angular velocity = 3.14/t = 3.14/0.144s = 21.82 rad/s
Therefore the RPM is 208 RPM (1 rad/s = 9.55 RPM)
Is this the right approach? Thank you.