Calculating Gas Pressure in a Piston System with Added Weight

AI Thread Summary
To calculate the gas pressure in a piston system with a 0.5 kg weight, the force exerted by the weight (mg) must be divided by the area of the piston to determine the pressure. The initial pressure is 1 atmosphere, and the added weight increases the pressure based on the area of the piston. The volume of the gas can be calculated using the ideal gas law, PV=nRT, once the new pressure is established. To achieve a volume of zero, the pressure must be infinitely high, requiring an impractical amount of mass on the piston. Understanding the relationship between force, pressure, and area is crucial for solving these types of problems.
dragon162
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Homework Statement


Suppose the system is at room temperature, 300 kelvin, and that before we put weights on top of the plunger in the cylinder the pressure inside is 1 atmosphere.

1)If i place a .5kg block on top of the piston, what is the pressure of the gas inside the cylinder?
2)At that pressure what is the volume of the gas?
3)If i want to have L=0cm what should the pressure be?
4)how much mass would we have to pile on top of the piston to achieve that pressure inside the system?

Homework Equations


PV=nRT
Volume of piston is V=L*A


The Attempt at a Solution


Ok I am confused as how to find the pressure of the gas when the block is added to the piston. Since the block is on the piston doesn't it apply a pressure of mg, (.5kg)(9.8)=4.9?

The second part is obvious, just use PV=nRT but I have to find the pressure in part 1 first. As for the other two I don't know how to start them but I am focused on the first part right now.
 
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dragon162 said:

The Attempt at a Solution


Ok I am confused as how to find the pressure of the gas when the block is added to the piston. Since the block is on the piston doesn't it apply a pressure of mg, (.5kg)(9.8)=4.9?
mg would be a force, not a pressure. The block applies a force of mg. To get the pressure, you would need to know the area of the piston's face. Without that information, the problem cannot be solved.
 
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