Calculating Gravitational Force between Neptune and the Sun

AI Thread Summary
To calculate the gravitational force between Neptune and the Sun, the masses of both celestial bodies are derived from Earth's mass, with the Sun being 332,800 times and Neptune 17 times Earth's mass. The gravitational constant is 6.67 x 10^-11 N m²/kg², and Neptune's average orbital radius from the Sun is 4503.99 x 10^9 m. The initial calculation attempted was incorrect, yielding 6.67 x 10^20 N, which did not match the expected answer format of x10^21 N. The user expressed frustration over the lack of assistance in resolving the calculation error. Accurate calculations are essential for determining the gravitational force accurately.
Axson
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Homework Statement



The mass of the sun is 332800 times that of the mass of Earth. The mass of neptune is 17 times that of the mass of the Earth. If the average orbital radius (distance from the sun) of neptune is 4503.99 x109 m, calculate the average gravitational force that neptune experiences due to the sun. Express your answer in units of 1021 N.
(The gravitational constant is 6.67 x 10^-11 N m2/kg2 and the mass of Earth is 5.98 x10^24 kg.)


The Attempt at a Solution



ok so i set up the problem like this..

(6.67 x 10^-11)(1.0166 x 10^26)(1.99 x 10^36) all over
(4503.99 x 10^9)^2

= 6.67 x 10^20 - which is wrong; I've used 1/3 tries on lon-capa and i kinda want to know what I am doing wrong here..

** to get the mass of the sun and neptune i just times them by the mass of Earth (5.98 x10^24)(17) for neptune and (5.98 x10^24)(332800) for the sun
 
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the answer is given as

something x10^21 N
 
solved it.. thanks for no help
 

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