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pete06
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A uniform rod of mass M = 20kg and length L = 5m is bent into a semicircle. What is the gravitational force exerted by the rod on a point mass m = 0.1 kg located at the center of curvature of the circular arc?
Gravitational force is a natural phenomenon of attraction between two objects with mass. It is the force that keeps planets in orbit around the sun and holds objects to the surface of the Earth.
Gravitational force is measured in units of Newtons (N). The force between two objects can be calculated using the equation F = G * (m1 * m2)/d^2, where G is the gravitational constant, m1 and m2 are the masses of the objects, and d is the distance between them.
The strength of gravitational force is affected by the masses of the objects and the distance between them. The larger the masses of the objects and the closer they are to each other, the stronger the gravitational force between them will be.
Gravitational force is a long-range force that acts between objects with mass, while other forces such as electromagnetic force and strong and weak nuclear forces act on a smaller scale between particles. Gravitational force is also always attractive, while other forces can be either attractive or repulsive.
No, gravitational force cannot be shielded or cancelled out. It is a fundamental force of nature that cannot be eliminated or blocked. However, its effects can be counteracted by other forces, such as the upward force of a chair supporting your weight against the Earth's gravitational force.