Calculating Gravitational Force on a Point Mass in a Semicircular Rod

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SUMMARY

The discussion focuses on calculating the gravitational force exerted by a uniform semicircular rod of mass M = 20kg and length L = 5m on a point mass m = 0.1kg located at the center of curvature. The key approach involves breaking the rod into differential mass elements (dm) and determining the y components of the gravitational force from each segment. By leveraging symmetry, the x components cancel out, allowing for the integration of the y components over the angle of the semicircle to find the total gravitational force.

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pete06
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A uniform rod of mass M = 20kg and length L = 5m is bent into a semicircle. What is the gravitational force exerted by the rod on a point mass m = 0.1 kg located at the center of curvature of the circular arc?
 
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I have assumed that this must be solved using the summation of all points on the rod since each exerts its own force on the point mass. Assuming that to be true, I figured that the x components all cancel each other out, leaving only the y components. But now, I don't know how to solve this?
 
You are on the right track. You have the symmetry figured out. Break the rod up into bits of mass dm and write the y component of the force related to each bit of mass. Add all the y components (integrate over the masses). This is most easily done by converting to an integral over an angle.
 

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