Calculating Gravity: Understanding Orbital Satellites in Circular Orbit

  • Thread starter Thread starter Didia
  • Start date Start date
Didia
Messages
2
Reaction score
0
this is one of the questions on my homework for today... can you guys explain to me how you will be able to get the answer for this?

-
-
-
A satellites are placed in a circular orbit that is 2.3.59E7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance? :confused:
 
Physics news on Phys.org
Didia said:
this is one of the questions on my homework for today... can you guys explain to me how you will be able to get the answer for this?

-
-
-
A satellites are placed in a circular orbit that is 2.3.59E7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance? :confused:

You need to know the universal gravitation law for the force of attraction between two objects. Then apply Newton's Second Law to find the acceleration of an object at that distance from the earth. You will find that the mass of the object does not matter. If you don't recognize the things I mentioned, find them in your text or search the internet.
 

Thread 'Initial conditions for orbits around a wormhole'

Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
View full post »

Thread 'Help to convert units of a simple formula'

The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
View full post »

Similar threads

What is the relationship between tension and mass for an artificial satellite?
Replies
10
Views
2K
Period of Satellite's Orbital Motion Around Earth
Replies
3
Views
2K
B Nodal Precession: Satellites Orbiting Earth Explained
Replies
22
Views
3K
B Gravity and speed of information for orbiting planets
Replies
22
Views
545
Using the path equation to determine the path of a satellite
Replies
1
Views
1K
Accelerating a satellite in a circular orbit
Replies
24
Views
3K
Satellite Position: Calculating ECI from ECEF
Replies
4
Views
3K
Potential Energy and raising a satellite from Earth into a Circular Orbit
Replies
5
Views
2K
I Time dilatopause for black holes
Replies
36
Views
4K
I Reasoning for circular/elliptical orbits
2
Replies
58
Views
4K

Hot Threads

Recent Insights

Back
Top