Calculating Heat Energy from Falling Object

AI Thread Summary
To calculate the heat energy produced by a 16 kg object dropped from 25 m, one must consider the conservation of energy, specifically the potential energy converted to kinetic energy and then to heat due to air friction. The potential energy (mgh) of the object is 3,920 J, while the kinetic energy at impact is 2,880 J. The difference, which accounts for energy lost to air friction, is 1,040 J. The correct answer to the heat energy produced is not explicitly listed in the options provided, indicating a possible miscalculation or misunderstanding of energy conservation principles. Understanding these concepts is crucial for solving similar physics problems effectively.
dragon513
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Calculating heat energy...

Q. #1
A 16 kg object is dropped from a height of 25 m and strikes the ground with a speed of 18 m/s. How much heat energy was produced during the fall?

Choices
A) 0 J
B) 2 600 J
C) 1 300 J
D) 3 900 J

Well,according to my calculation, the average acceleration was about 6.48m/s, which means 3.32N/kg acted as air friction.

And I'm lost from there.

Help will be greatly appreciated!
 
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HINT: Energy is conserved! :)
 
Like Tide said remember

\Delta K + \Delta U = W_{friction}
 
dragon513 said:
Q. #1
A 16 kg object is dropped from a height of 25 m and strikes the ground with a speed of 18 m/s. How much heat energy was produced during the fall?
Choices
A) 0 J
B) 2 600 J
C) 1 300 J
D) 3 900 J
Well,according to my calculation, the average acceleration was about 6.48m/s, which means 3.32N/kg acted as air friction.
And I'm lost from there.
Help will be greatly appreciated!
You don't have to work out force or average speed. Just use potential energy: mgh.

AM
 
ouch, I learned that a year ago and I have no idea how can I forget such thing ...Thx!
 

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