Calculating Heights on the Ferris Wheel

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The discussion focuses on calculating the height of a seat on a Ferris Wheel designed by George Ferris in 1893, with a diameter of 250 feet and a revolution time of 50 seconds. The height function h(t) is given as h(t) = 125sin(pi/25t - pi/2) + 125. Participants are seeking to determine specific times when the height reaches 125 feet and 250 feet, as well as intervals when the height exceeds 125 feet. The initial query is about solving for when h(t) equals 125 feet during the first 50 seconds of the ride. The conversation emphasizes solving the equation for t to find these height values.
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In 1893, George Ferris engineered the Ferris Wheel. It was 250 feet in diameter. If the wheel makes 1 revolution every 50 seconds, then

h(t) = 125sin (pi/25t - pi/2) + 125

represents the height (h), in feet, of a seat on the wheel as a function of time (t), where t is measured in seconds. The ride begins when t = 0.


a.) During the first 50 seconds of the ride, at what time (t) is an individual on the Ferris Wheel exactly 125 feet above the ground?

b.) During the first 100 seconds of the ride, at what time (t) is an individual on the Ferris Wheel exactly 250 feet above the ground?

c.) During the first 50 seconds of the ride, over what interval of time (t) is an individual on the Ferris Wheel more than 125 feet above the ground?

Can someone help me solve part A so I can do the rest by myself. Thank you very much!
 
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urthatarget said:
a.) During the first 50 seconds of the ride, at what time (t) is an individual on the Ferris Wheel exactly 125 feet above the ground?

They are simply saying, during one revolution, when is h(t) = 125. Solve for t.
 
urthatarget said:
In 1893, George Ferris engineered the Ferris Wheel. It was 250 feet in diameter. If the wheel makes 1 revolution every 50 seconds, then

h(t) = 125sin (pi/25t - pi/2) + 125
You mean h(t)= 125 sin((pi/25)t- pi/2)+ 125

represents the height (h), in feet, of a seat on the wheel as a function of time (t), where t is measured in seconds. The ride begins when t = 0.


a.) During the first 50 seconds of the ride, at what time (t) is an individual on the Ferris Wheel exactly 125 feet above the ground?
Solve the equation h(t)= 125 sin((pi/25)t- pi/2)+ 125= 125. For what values of x is sin(x)= 0?

b.) During the first 100 seconds of the ride, at what time (t) is an individual on the Ferris Wheel exactly 250 feet above the ground?

c.) During the first 50 seconds of the ride, over what interval of time (t) is an individual on the Ferris Wheel more than 125 feet above the ground?

Can someone help me solve part A so I can do the rest by myself. Thank you very much!
 
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