Calculating Ice Melt from Heat Generated by a 54kg Skater Skating at 6.4 m/s"

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A calculation was performed to determine the amount of ice melted by a 54kg skater skating at 6.4 m/s who stops, with 50% of the generated heat transferred to the ice. The result showed that 1.6 grams of ice would melt, which surprised some participants due to its small quantity. The latent heat of fusion for ice was confirmed as 3.33 x 10^5 J/kg, validating the calculations. Participants humorously noted that the small amount of melted ice was reasonable, as one skater would not significantly affect an entire rink. Overall, the discussion highlighted the physics behind heat transfer and ice melting in a skating scenario.
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A 54kg ice skater skating at 6.4 m/s stops. If 50% of the heat generated is transferred to the ice, calculate how much ice is melted.

My solution:

(54 x 6.4^2)/2 = 1106 J

1106 x 0.5 = 553 J

553 = m x 3.33 x 10^5 (3.33 x 10^5 is latent heat of fusion of ice)

m = 1.6 grams

It sounds too small to be true, can someone verify please?
 
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If the unit for ice melting latent heat is J/Kg,then it's okay...

Why surprised??

Daniel.
 
Link,

You are correct.

- Warren
 
Hey, you can hardly expect the whole skating rink to melt just because one skater comes to a halt!
 
lol thanks guys! I tend to doubt my calculations sometimes... I was expecting something on 10 grams :smile:
 

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