Calculating Impulse for a Truck Slowing Down: Momentum and Vector Help

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To calculate the impulse for a truck slowing down, the impulse-momentum theorem is applied, which states that impulse equals the change in momentum. The formula used is impulse = m(delta)(vf - vi), where m is the mass, vf is the final velocity, and vi is the initial velocity. For a truck with a mass of 1.20 x 10^3 kg slowing from 24.0 m/s to 10.4 m/s, the impulse can be calculated directly without needing to factor in time. The impulse is determined by the mass and the change in velocity, resulting in a specific magnitude and direction. Understanding that impulse is independent of time is crucial for this calculation.
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i know that the formula for impulse is f(delta)t. my question ask " a truck with a mass of 1.20 x 10^3 kg has its brakes applied for 5.50s as it slows down from 24.0m/s, west to 10.4m/s west. determine the magnitude and direction of the impulse provided by the brakes." i know you need to use the formula
f(delta)t = m(delta)(vf-vi). but since i want the impulse do i just fill in the right side of the formula and git impulse or do i use the time also. thanks.
 
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u can safely ignore "time=5.50s" as impulse is independant of time.


just impulse= (1.20 x 10^3)(24.0-10.4)
 
The impulse is the left-hand-side: (Favg)(Delta t).
By the impulse-momentum theorem, it then follows that it is equal to the change-in-momentum.
 
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