Calculating Impulse in a Collision: Simple Physics 11 Homework Problem

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    Physics Physics 11
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To calculate the impulse applied by the 45.0 g object to the 15.0 g object during the collision, the change in velocity of the 15.0 g object must be determined. The initial velocity of the 15.0 g object is 30.0 cm/s to the right, and after the collision, it must be calculated based on the conservation of momentum. The correct impulse is found using the formula FΔt = mΔv, ensuring units are converted to standard SI units (kg and m/s). The impulse calculated should be 6.75 x 10^-3 N·s, indicating a misunderstanding in the initial calculations. Proper unit conversion and momentum analysis are crucial for solving this physics problem accurately.
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Homework Statement



A 15.0 g object initially moving to the right at 30.0 cm/s collides with a stationary 45.0 g object. After the collision the 45.0 g object is moving to the right at 15 cm/s.
what impulse does the 45.0 g object apply to the 15.0g object during collision?

Homework Equations



F\Deltat = m\Deltav

The Attempt at a Solution



I tried:
F\Deltat = m\Deltav
= (15.0g)(15.0cm/s)
= 225 N x s
but the answer is 6.75 x 10^-3 N x s
help ?
 
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roxxyroxx said:
I tried:
F\Deltat = m\Deltav
= (15.0g)(15.0cm/s)
= 225 N x s
but the answer is 6.75 x 10^-3 N x s
How did you determine the change in velocity of the 15.0g object?

(Also: Use standard units. Convert g to kg; cm to m.)
 
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