Calculating Induced Voltage in a Rotating Rectangular Loop with Magnetic Field

  • Thread starter Thread starter lazyaditya
  • Start date Start date
AI Thread Summary
To calculate the induced voltage in a rotating rectangular loop, the loop's dimensions are 30 cm by 40 cm, rotating at 130 rad/sec in a magnetic field of 0.06 Wb/m². The magnetic field is perpendicular to the axis of rotation, meaning it passes directly through the loop. The discussion emphasizes using Faraday's law of induction, which relates the induced electromotive force (emf) to the rate of change of magnetic flux. The participants clarify that the changing position of the conductor affects the magnetic flux, which is essential for calculating the induced voltage. The conversation concludes that the approach using flux calculations is effective for this scenario.
lazyaditya
Messages
176
Reaction score
7
Q. A 30 cm by 40 cm rectangular loop rotates at 130 rad/sec in a magnetic field 0.06Wb/metre sqre normal to the axis of rotation. If the loop has 50 turns, determine the induced voltage in the loop ?

Attempt !

V(induced) in 1 turn = ∫(u X B).dS

my vector u will be ρω in a∅ direction but i am unable to understand the direction of magnetic field what does it mean by direction perpendicular to axis of rotation ?
 
Physics news on Phys.org
lazyaditya said:
Q. A 30 cm by 40 cm rectangular loop rotates at 130 rad/sec in a magnetic field 0.06Wb/metre sqre normal to the axis of rotation. If the loop has 50 turns, determine the induced voltage in the loop ?

Attempt !

V(induced) in 1 turn = ∫(u X B).dS

my vector u will be ρω in a∅ direction but i am unable to understand the direction of magnetic field what does it mean by direction perpendicular to axis of rotation ?

It means that the magnetic field goes straight through the loop. Say that the loop's axis of rotation is the x direction, then the magnetic field could be in the y or z direction.
 
lazyaditya said:
Q. A 30 cm by 40 cm rectangular loop rotates at 130 rad/sec in a magnetic field 0.06Wb/metre sqre normal to the axis of rotation. If the loop has 50 turns, determine the induced voltage in the loop ?

Attempt !

V(induced) in 1 turn = ∫(u X B).dS

my vector u will be ρω in a∅ direction but i am unable to understand the direction of magnetic field what does it mean by direction perpendicular to axis of rotation ?

I think it would be easier to use Farady's law of induction which equates emf to rate of change of magnetic flux.
 
berkeman said:
It means that the magnetic field goes straight through the loop. Say that the loop's axis of rotation is the x direction, then the magnetic field could be in the y or z direction.

but then if i am considering the direction of rotation to be A∅ wouldn't both the directions Aρ
and Az will be perpendicular to it !
 
rude man said:
I think it would be easier to use Farady's law of induction which equates emf to rate of change of magnetic flux.
how should i use faraday law in this the conductor position is changing ! wouldn't the faraday law equation result in the equation i have used in the end !
 
lazyaditya said:
how should i use faraday law in this the conductor position is changing ! wouldn't the faraday law equation result in the equation i have used in the end !

Yes, the conductor position is changing. That's what makes the magnetic flux change, since flux = B dot area where B and area are vectors ...

Yes, yopur equation is tantamount to farady's law. i just meant that using flux = B x A is easier ...
 
Back
Top