Calculating Initial Velocity in Vertical Projectile Motion

AI Thread Summary
A mountain climber throws two stones from a 50m cliff, with the first stone thrown at an initial speed of 2 m/s. Both stones hit the water simultaneously, despite the second stone being thrown 1 second later. The calculations involve using kinematic equations to determine the time it takes for the first stone to reach the water and subsequently find the initial velocity of the second stone. The model answer suggests an initial speed of 15.2 m/s for the second stone, which raises questions about the calculations. The key to solving the problem lies in accurately determining the time of flight for both stones.
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Homework Statement


A mountain climber stands at the top of a 50m cliff that overhangs a calm pool. She throws two stones vertically download 1s apart and observe that the two stones reach the water simultaneously after a while. The first stone was thrown at an initial speed of 2m^{-1}.s

Calculate the initial speed at which she threw the second stone. Ignore the effects of friction


Homework Equations





The Attempt at a Solution


Vf^{2}=V_{i}^{2} + a\Deltay
=2(2)^{2}=2(9.8)(50)=31.37
Vf=5.6m.s^{-1}

V_{f}=v_{i}+at
5.6=2+9.8t
t=0.367...
t=0.37s

I am not sure if I am right...because now i have to -1 second from the t above hence giving me a negative second to enter in a formula to find the initial velocity of the stone...

Can someone help me...the model answer gives me an anser of 15.2m/s downwards...how can that be? surely it is wrong
 
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Find how long it takes the first rock to reach the water, that also will let you easily find the time the second rock was in the air. Then just solve for Vo.
 
i did an i get 0.37s...and if the the second stone was released 1 s later then how can that be?
 
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