GrandMaster87
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Homework Statement
A mountain climber stands at the top of a 50m cliff that overhangs a calm pool. She throws two stones vertically download 1s apart and observe that the two stones reach the water simultaneously after a while. The first stone was thrown at an initial speed of 2m^{-1}.s
Calculate the initial speed at which she threw the second stone. Ignore the effects of friction
Homework Equations
The Attempt at a Solution
Vf^{2}=V_{i}^{2} + a\Deltay
=2(2)^{2}=2(9.8)(50)=31.37
Vf=5.6m.s^{-1}
V_{f}=v_{i}+at
5.6=2+9.8t
t=0.367...
t=0.37s
I am not sure if I am right...because now i have to -1 second from the t above hence giving me a negative second to enter in a formula to find the initial velocity of the stone...
Can someone help me...the model answer gives me an anser of 15.2m/s downwards...how can that be? surely it is wrong