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How Do You Calculate Instantaneous Acceleration?
- Thread starter Miike012
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Instantaneous acceleration is defined as the rate of change of velocity over time. To calculate it, one must take the derivative of the velocity function rather than simply subtracting two velocity values. The formula a = (v - vo) / t can be used, where 'a' is acceleration, 'v' is final velocity, 'vo' is initial velocity, and 't' is time. Understanding this concept is essential, even for those not studying calculus-based physics. Properly applying these principles will lead to accurate calculations of instantaneous acceleration.
- #2
Dembadon
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Acceleration is the rate of change of velocity.
- #3
Miike012
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ok for velocity I got 10.1 m/s and 10.25 m/s ...
so substract them is what you are telling me?
so substract them is what you are telling me?
- #4
Dembadon
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Both are functions of time, so just subtracting them will not be sufficient. Do you know a function for acceleration you can use? You can obtain it by taking the derivative of the function for velocity.
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Miike012
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im not in calc based phy
- #6
Dembadon
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I see, sorry about that.
Here's some information that you can use to solve this problem. I don't want to tell you too much because it is good for you to think about it.
a=(v-vo)/t
where
a=acceleration (m/s2)
v=final velocity (m/s)
vo=initial velocity (m/s)
t=time (s).
Here's some information that you can use to solve this problem. I don't want to tell you too much because it is good for you to think about it.
a=(v-vo)/t
where
a=acceleration (m/s2)
v=final velocity (m/s)
vo=initial velocity (m/s)
t=time (s).
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook.
Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water.
I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
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