Calculating Iterated Integrals - 2e4

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1. The problem statement, all variables and given/known data

Calculate the given iterated integrals ∫02 dy ∫0yy2 * exy dxMy attempt:

20dy[exy*y]y0

= ∫20 ey*y*y - ex*0*0

= ∫20ey2*y dx

= [ey^2]*y]20 = 2e4

Is this correct?
 
Last edited:
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Kork said:
1. The problem statement, all variables and given/known data

Calculate the given iterated integrals ∫02 dy ∫0yy2 * exy dx
I think you skipped a step going from the above to the line below. Written in a more usual form, your integral would be
\int_{y = 0}^2~\int_{x = 0}^y y^2 e^{xy}~dx~dy

(You can see what I did in LaTeX by clicking the integral above.)
Show how you get from the step above to the step where you've carried out the inner integration.


Kork said:
My attempt:

20dy[exy*y]y0

= ∫20 ey*y*y - ex*0*0

= ∫20ey2*y dx

= [ey^2]*y]20 = 2e4

Is this correct?

No - see above. I get (1/2)e4 - 5/2
 
I don't understand what I have done wrong at all
 
The error is here:
\left . ye^{xy}\right |_{x = 0}^y

You need to replace x by 0, not y.
 
Im still confused I get:

[ey^2*y-y]20 =

(e^2^2 - 2) - (e^0^2 - 0) =

2e^4 - 2 ?

Im lost
 
You're skipping steps. You have the outer integrand right, but you have made a mistake when you integrated this integral.
\int_0^2 (ye^{y^2} - y)dy

Split this into two integrals and carry out the two integrations.
 
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Oh I have totally lost my comprehensive view now...
 
Kork said:
Oh I have totally lost my comprehensive view now...
I don't know what you mean by this.
 
How do I get from:

= ∫(y = 0 to 2) (ye^(y^2) - y) dy

= (1/2)e^(y^2) - (1/2)y^2 {for y = 0 to 2}

?
 
  • #10
y0 ye^(y^2) - y dy

to

= (1/2)e^(y^2) - (1/2)y^2


{for y = 0 to 2}
 
  • #11
Split the integral into two.
Use substitution to do the first integral.
 
  • #12
This didnt get me further from start, but thanks anyway.
 
  • #13
Kork said:
y0 ye^(y^2) - y dy

to

= (1/2)e^(y^2) - (1/2)y^2
When you evaluate the above at 2 and 0, what do you get?

Sorry, I misunderstood what you were asking before.
Kork said:
{for y = 0 to 2}
 
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