Calculating Jupiter's Mass from Orbital Data

  • Thread starter Thread starter BoldKnight399
  • Start date Start date
  • Tags Tags
    Data Mass Orbital
AI Thread Summary
The discussion revolves around calculating Jupiter's mass using Io's orbital data, specifically its period and radius. Initial attempts at using the formula T^2 = (4π^2/(G*Mj)) * R^3 led to incorrect values for Jupiter's mass. Participants pointed out errors in calculations, such as misusing units and incorrectly applying the formula. After several adjustments, including correcting the radius to meters and ensuring proper squaring of values, the correct mass of Jupiter was determined to be approximately 3.16 x 10^27 kg. The conversation highlights the importance of precision in physics calculations.
BoldKnight399
Messages
78
Reaction score
0
Io, a satellite of Jupiter, has an orbital period of 1.43 days and an orbital radius of 4.35X10^5 km. From this data, determine the mass of Jupiter.

So step one: I cried.
then I tried to use the equation:
T^2=4(pi)^2/(GXMj) X R^3
thus
(123552)^2= (39.478)/(6.672X10^-11)(Mj) X (4.34X10^5)^3

35161.29=(39.478)/(6.672X10^-11)(Mj) X (8.17465X10^16)

Mj=1.3756X10^24

Apparently I was wrong...
Anyone have any ideas what I did to mess this up?
 
Physics news on Phys.org
Hi BoldKnight399! :smile:

(please don't use X for "times" … either use * or nothing … oh and have a pi: π and try using the X2 tag just above the Reply box :wink:)
BoldKnight399 said:
(123552)^2= (39.478)/(6.672X10^-11)(Mj) X (4.34X10^5)^3

35161.29=(39.478)/(6.672X10^-11)(Mj) X (8.17465X10^16)

I'm not sure what your fomula is :redface:, but anyway where did 35161.29 come from (did you take a square-root instead)?
 
I just used the formula:
T^2=(4(Pi)^2/G*M)*R^3

and i have no idea what I did to get 35161.29 in addition, what do you mean about having pi=n?
 
ok so I tried it then having the time correctly squared:
(1.526X10^10)=(39.478/(6.673*10^-11)(M)) * (8.321*10^16)
and i got that the Mass of Jupiter was 3.19*10^18

that was wrong. I don't understand what I am doing wrong
 
(please use the X2 tag just above the Reply box)

Try using m instead of km ! :wink:

(oh, and it wasn't n, it was π :biggrin:)
 
alright, so it became:
(1.526X10^10)=(39.478/(6.673*10^-11)(M)) * (8.321*10^19)
M=3.2259*10^21

still wrong. I thought I had everything right.
 
erm :redface:

cubed? :smile:
 
wow...I am not having a good physics day I guess. Thank you so much. I got:
3.16*10^27 and that was right.
 
Back
Top