Calculating Kinetic Energy for Solving PE and KE Problems

  • Thread starter Thread starter I NEED HELP
  • Start date Start date
  • Tags Tags
    Physics
AI Thread Summary
To calculate kinetic energy (KE) from potential energy (PE), one must understand the principle of conservation of energy, which states that the total mechanical energy remains constant in a closed system. If a body is falling, the potential energy converts into kinetic energy as it descends. The equation for kinetic energy is KE = PE_initial - PE_final, where PE_final is zero at the lowest point. For a body falling from a height, the initial potential energy can be equated to the kinetic energy just before impact. Understanding these concepts will enable the calculation of KE based on the given potential energy values.
I NEED HELP
Messages
3
Reaction score
0
Energy Question?

OK let's say that PE=15000 or 11250 J (J=Joules) how would you find out what the KE is?

just want to find out how to get the Kinectic Energy?
 
Last edited:
Physics news on Phys.org
Need Help?
 
You need to show equations and an attempt at the answer
 
I NEED HELP said:
OK let's say that PE=15000 or 11250 J (J=Joules) how would you find out what the KE is?

just want to find out how to get the Kinectic Energy?

Saying that potential energy is 11250J is meaningless really.
Is there some sort of problem associated with the potential energy? A body falling? Something of that sort?
 
ok then let's say it's a body falling how do i answer this...i don't want you to give me the answer i need help so i can understand this and solve it to get the answer on my own...
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top